x^2-34x+25=0

Solution for x^2-34x+25=0 equation:

x^2-34x+25=0

a = 1; b = -34; c = +25;
Δ = b2-4ac
Δ = -342-4·1·25
Δ = 1056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1056}=\sqrt{16*66}=\sqrt{16}*\sqrt{66}=4\sqrt{66}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-4\sqrt{66}}{2*1}=\frac{34-4\sqrt{66}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+4\sqrt{66}}{2*1}=\frac{34+4\sqrt{66}}{2}
$